C++ program to find the largest and second largest number present in an array

C++ program to find the largest and second-largest numbers present in an array along with their location index on the array. This program first find the largest number by going through all the numbers in the array. It stores the index of the largest number on the variable pos1 and largest number is the largest variable. A second for loop is applied, which also check for the largest number. When it hits on the largest found by the first loop, it is bypassed using a continue statement and hence will get the second-largest number.

#include <iostream>
#include <conio.h>
using namespace std;

void main()
{
	int a[10], i, largest = 0, second_largest = 0, pos1, pos2;
	int n;
	cout << "Enter Number of elements :";
	cin >> n;
	for (i = 0; i < n; ++i)
	{
		cout << "n Enter " << (i + 1) << "th Element :";
		cin >> a[i];
	}
	//Finding Largest
	for (i = 0; i < 10; ++i)
	{
		if (a[i] > largest)
		{
			largest = a[i];
			pos1 = i;
		}
	}
	//finding second largset
	for (i = 0; i < 10; ++i)
	{
		if (a[i] > second_largest)
		{
			if (a[i] == largest)
				continue;	//Ignoring largest in order to get second largest
			second_largest = a[i];
			pos2 = i;
		}
	}
	cout << "nn Largest Number :" << largest << " at position " << (pos1 + 1);
	cout << "nn Second Largest Number :" << second_largest << " at position " << (pos2 + 1);

	getch();
	return;
}

*Compiled using Visual Studio

Output